If \(\frac{1}{x}\) is a positive fraction and \(\frac{1}{y}\) is a negative fraction, then which of the following statements are true? (A) \(\frac{1}{x} + \frac{1}{y}\) is positive (B) \(\frac{1}{x} - \frac{1}{y}\) is positive (C) \(\frac{x - y}{xy}\) is negative (D) \(\frac{1}{xy}\) is positive (E) \(\frac{1}{x} - \frac{1}{y}\) is positive
To determine which statements are true, let’s analyze each option individually.
Statement (A): \( \frac{1}{x} + \frac{1}{y} \) is positive.
\( \frac{1}{x} \) is a positive fraction.
\( \frac{1}{y} \) is a negative fraction.
Adding a positive number and a negative number results in a number whose sign depends on their magnitudes.
Without specific values, we cannot conclude that \( \frac{1}{x} + \frac{1}{y} \) is positive.
Statement (B): \( \frac{1}{x} - \frac{1}{y} \) is positive.
Subtracting a negative fraction \( \frac{1}{y} \) from a positive fraction \( \frac{1}{x} \) can be written as:
\[ \frac{1}{x} + \left(-\frac{1}{y}\right) = \frac{1}{x} + \frac{1}{y} \],
where the second fraction is actually positive.
Therefore, \( \frac{1}{x} - \frac{1}{y} \) is positive.
Statement (C): \( \frac{x - y}{xy} \) is negative.
Since \( \frac{1}{x} \) is positive, \( x \) must be positive.
Since \( \frac{1}{y} \) is negative, \( y \) must be negative.
As a result, \( xy \) (product of a positive and a negative) is negative.
Because \( xy \) is negative,
\(\frac{x - y}{xy} \) has a negative denominator.
Thus, \( \frac{x - y}{xy} \) is negative.
Statement (D): \( \frac{1}{xy} \) is positive.
We already established \( xy \) is negative.
Therefore, \( \frac{1}{xy} \), which has a positive numerator and a negative denominator, is negative, not positive.
Statement (E): \( \frac{1}{x} - \frac{1}{y} \) is positive.
This is the same concept as Statement (B).
This statement is indeed positive, as already explained.
Analyzing each statement demonstrates that only Statement (B) and Statement (C) hold true. Thus, the correct answer is: Only (B) & (C) are true.