We are given that 1 man or 2 women can finish a job in 20 days. This implies the work done by 1 man in 1 day is \( \frac{1}{20} \), and the work done by 1 woman in 1 day is \( \frac{1}{40} \) (since 2 women together can finish the job in 20 days, so 1 woman will take 40 days).
Now, for 3 men and \( x \) women working together, their combined work per day will be:
\[
\text{Work per day} = 3 \times \frac{1}{20} + x \times \frac{1}{40}
\]
The total work done in 1 day by the group is equal to \( \frac{1}{4} \), so:
\[
3 \times \frac{1}{20} + x \times \frac{1}{40} = \frac{1}{4}
\]
Solving this equation:
\[
\frac{3}{20} + \frac{x}{40} = \frac{1}{4}
\]
Multiplying through by 40 to eliminate the fractions:
\[
6 + x = 10
\]
\[
x = 4
\]
Thus, the number of women working is 4, and the total number of workers is 3 men and 4 women. The time required to complete the job will be:
\[
\text{Time} = \frac{1}{\text{Work per day}} = \frac{1}{\frac{1}{4}} = 4 \text{ days}
\]
Thus, the answer is \( 4 \) days.