Question

Identify the statement which is not correct regarding \(CuSO_4\).

• A. It reacts with KI to give iodine
• B. It reacts with KCl to give \(Cu_2Cl_2\)
• C. It reacts with NaOH and glucose to give \(Cu_2O\)
• D. It gives CuO on strong heating in air

Hint:

\(CuSO_4\) gives iodine with KI, gives \(Cu_2O\) with glucose + NaOH, and decomposes to CuO on heating. Simple KCl cannot reduce it to \(Cu_2Cl_2\).

Answer 1

The Correct Option is B

Step 1: Check statement (A).
\[ 2CuSO_4 + 4KI \rightarrow 2CuI + I_2 + 2K_2SO_4 \] So iodine is produced \(\Rightarrow\) (A) correct.
Step 2: Check statement (C).
In alkaline medium with reducing sugar (glucose), \(Cu^{2+}\) reduces to \(Cu_2O\) (brick red).
So (C) correct.
Step 3: Check statement (D).
On heating \(CuSO_4\):
\[ CuSO_4 \xrightarrow{\Delta} CuO + SO_3 \] So (D) correct.
Step 4: Check statement (B).
KCl does not reduce \(Cu^{2+}\) to \(Cu^{+}\) to form \(Cu_2Cl_2\).
So statement (B) is incorrect.
Final Answer: \[ \boxed{\text{(B) is not correct}} \]