Zinc is an amphoteric metal, meaning it reacts with both acids and bases. When zinc reacts with a strong base like sodium hydroxide (NaOH), it dissolves, forming sodium zincate (\( \text{Na}_2\text{ZnO}_2 \)) and hydrogen gas (\( \text{H}_2 \)).
Step 2: Writing the balanced chemical equationThe reaction proceeds as:
\[ \text{Zn} + 2\text{NaOH} + 2\text{H}_2\text{O} \rightarrow \text{Na}_2\text{ZnO}_2 + \text{H}_2 \]This shows that sodium zincate and hydrogen gas are the products of the reaction.
Step 3: Explanation of the reaction mechanismZinc initially reacts with hydroxide ions (\( \text{OH}^- \)) from sodium hydroxide. This forms a complex ion \( \text{Zn(OH)}_4^{2-} \) in aqueous solution.
The sodium ions (\( \text{Na}^+ \)) associate with the zincate ion to form sodium zincate \( \text{Na}_2\text{ZnO}_2 \).
Simultaneously, hydrogen gas (\( \text{H}_2 \)) is released.
Step 4: Verifying the correct optionAmong the given options, only option (2) correctly represents the formation of sodium zincate (\( \text{Na}_2\text{ZnO}_2 \)) along with hydrogen gas (\( \text{H}_2 \)), making it the right choice.
Quick tip: Zinc’s amphoteric nature allows it to react with both acids and bases to form different products, like zincate when reacting with bases.
To solve the problem, we need to determine the products formed when zinc reacts with sodium hydroxide solution.
1. Understanding the Reaction:
When zinc reacts with sodium hydroxide (\( \text{NaOH} \)), the reaction produces sodium zincate (\( \text{Na}_2\text{ZnO}_2 \)) and hydrogen gas (\( H_2 \)) as the products. The reaction can be written as:
2. Conclusion:
Based on the given reaction and products, the correct answer is:
Final Answer:
The correct option is (B) \( \text{Na}_2\text{ZnO}_2 + H_2 \).
In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ___________%. [Given: Molar mass in g mol\(^{-1}\) of Ag = 108, Cl = 35.5]