Identify the option that will replace the question mark. 
Step 1: Understanding the Concept:
This is a matrix reasoning problem where one must identify the underlying rules governing the elements in a 3x3 grid to determine the missing element. The rules can apply to rows, columns, or the entire grid.
Step 2: Key Formula or Approach:
We can analyze the properties of the tiles in the grid, such as background color (white or black) and the density of dots (sparse, medium, dense). Let's check for patterns in rows and columns.
Step 3: Detailed Explanation:
Let's analyze the background colors first.
Row 1: White, White, White.
Row 2: Black, ?, White.
Row 3: Black, Black, White.
Column 1: White, Black, Black.
Column 2: White, ?, Black.
Column 3: White, White, White.
Notice the pattern in the columns. Column 1 has one white and two black backgrounds. Column 3 has three white backgrounds. For the pattern to have some symmetry, it is logical that Column 2 should also have one white and two black backgrounds. Since Row 1, Column 2 is already white, and Row 3, Column 2 is black, the missing tile in Row 2, Column 2 must have a black background. This eliminates option (C).
Now let's analyze the density of dots: Sparse (S), Medium (M), Dense (D).
Row 1: S, M, D (A clear progression).
Column 3: D, S, M (A permutation of S, M, D).
Let's assume each row and column should contain a permutation of the three densities.
Row 2: D, ?, S. To complete the set {S, M, D}, the missing density must be Medium (M).
Column 2: M, ?, S. To complete the set {S, M, D}, the missing density must be Dense (D).
The density logic is contradictory. Let's re-examine the problem, as such puzzles can have multiple layers of logic. However, given the options, let's reconsider the first row's clear progression (S -> M -> D). Row 2 follows a similar progression but in reverse (D -> ? -> S). The most logical fill-in for this pattern is Medium (M). This fits the Row logic.
Combining our findings:
The background must be black.
The dot density is most likely medium.
The tile that fits these criteria is a black square with a medium density of white dots.
Step 4: Comparing with Options:
(A): Black background, medium density of dots. This matches our conclusion.
(B): Black background, sparse dots.
(C): White background.
(D): Black background, dense dots.
Option (A) is the most logical choice.



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Which option will replace the question mark? 