Reaction (a): Toluene is oxidized by KMnO₄/KOH to form benzoic acid (C₆H₅COOH). The methyl group (CH₃) is fully oxidized to a carboxylic acid group.
Reaction (b): Ethylbenzene is oxidized by KMnO₄/KOH to form phenylacetic acid (C₆H₅CH₂COOH). The ethyl group (CH₂CH₃) is partially oxidized to an acetic acid group.
Matching these products with the options confirms that the correct answer is (E).
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Approach Solution -2
- In reaction (a), toluene (C₆H₅CH₃) is oxidized to benzoic acid (C₆H₅COOH).
Thus, 1 = C₆H₅COOH.
- In reaction (b), ethylbenzene (C₆H₅CH₂CH₃) is oxidized to phenylacetic acid (C₆H₅CH₂COOH).
Aromatic hydrocarbons, sometimes known as arenes, are aromatic organic molecules made up entirely of carbon and hydrogen. In aromatic compounds a benzene ring which is named after the simple aromatic chemical benzene, or a phenyl group when part of a larger structure, is the configuration of six carbon atoms.
This reaction involves the replacement of one substituent on the ring of an aromatic hydrocarbon, commonly a hydrogen atom, by a different substituent group.
The common types of aromatic substitution reactions are:
