Question:

(i) $p \supset (q \cdot r)$ (ii) $\sim(p \supset s)$
Taking (i) and (ii) as premises, which of the following can be deduced?

Show Hint

Always convert implications using Material Implication ($p \supset q \equiv \sim p \lor q$). It often simplifies proofs when combined with De Morgan's Theorem.
Updated On: Aug 29, 2025
  • $q$
  • $r$
  • $s$
  • $\sim p$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A, B

Solution and Explanation


From (ii) $\ \sim(p \supset s)$, apply Material Implication: $p \supset s \equiv \sim p \lor s$. Hence \[ \sim(p \supset s)=\sim(\sim p \lor s)\stackrel{\text{De Morgan}}{=} \sim\sim p \ \cdot\ \sim s = p \ \cdot\ \sim s. \] So we have $p$ and $\sim s$.
Using (i) and Modus Ponens with $p$: \[ p, p \supset (q \cdot r) \ \Rightarrow\ q \cdot r. \] By Simplification: \[ q \cdot r \ \Rightarrow\ q \text{and} r. \] Thus (A) $q$ and (B) $r$ are deducible; (C) $s$ and (D) $\sim p$ are not.
Was this answer helpful?
0
0

Questions Asked in GATE XH- C4 exam

View More Questions