Question:
I am the smallest number, having four different prime factors. Can you find me?
I am the smallest number, having four different prime factors. Can you find me?
Updated On: Dec 15, 2023
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Solution and Explanation
The smallest four prime numbers are 2, 3, 5 and 7.
Hence, the required number is 2 x 3 x 5 x 7 = 210
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