Question:
Hydrolysis of $ XeF_4 $ and $ XeF_6 $ with water gives
Hydrolysis of $ XeF_4 $ and $ XeF_6 $ with water gives
Updated On: Jun 14, 2022
- $ XeOF_4 $
- $ XeO_2F_2 $
- $ XeO_3 $
- $ XeOF_2 $
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The Correct Option is C
Solution and Explanation
Hydrolysis of $XeF_4$ and $XeF_6$ with water gives various products but the common product is $XeO_3$, which is an explosive.
$6XeF_4 + 12H_2O {->} 2XeO_3 + 24HF$
$+ 4Xe + 3O_2$
$XeF_6 + 3H_2O {->} XeO_3 + 6HF$.
$6XeF_4 + 12H_2O {->} 2XeO_3 + 24HF$
$+ 4Xe + 3O_2$
$XeF_6 + 3H_2O {->} XeO_3 + 6HF$.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family