The correct option is(B): 1200 litres
Power=\(\frac{work \,done}{time\, taken}=\frac{w}{t}\)
but W - mass \(\times\) gravity \(\times\) height
\(\therefore \, \, \, \, \, p=\frac{M \times g \times h}{t}\)
\(\Rightarrow \, \, \, \, M=\frac{P \times t}{g \times h}=\frac{2000 \times 60}{10 \times 10}=1200 \,kg.\)
i.e. 1200 litres as one litre has a mass of 1 kg.
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec: