How much copper can be obtained from 100 g of copper sulphate \((\text{CuSO}_4)\)?
Solution and Explanation
1 mole of \((\text{CuSO}_4)\) contains 1 mole of copper.
Molar mass of \((\text{CuSO}_4)\) = (63.5) + (32.00) + 4(16.00)
= 63.5 + 32.00 + 64.00
= 159.5 g
159.5 g of \((\text{CuSO}_4)\) contains 63.5 g of copper.
⇒ 100 g of \((\text{CuSO}_4)\) will contain \(\frac{63.5 × 100\, \text{g} }{ 159.5}\) of copper.
Amount of copper that can be obtained from 100 g \((\text{CuSO}_4)\) \(= \frac{63.5 × 100\, \text{g} }{ 159.5}\)
= 39.81 g
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