1 mole of \((\text{CuSO}_4)\) contains 1 mole of copper.
Molar mass of \((\text{CuSO}_4)\) = (63.5) + (32.00) + 4(16.00)
= 63.5 + 32.00 + 64.00
= 159.5 g
159.5 g of \((\text{CuSO}_4)\) contains 63.5 g of copper.
⇒ 100 g of \((\text{CuSO}_4)\) will contain \(\frac{63.5 × 100\, \text{g} }{ 159.5}\) of copper.
Amount of copper that can be obtained from 100 g \((\text{CuSO}_4)\) \(= \frac{63.5 × 100\, \text{g} }{ 159.5}\)
= 39.81 g
Fortification of food with iron is done using $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$. The mass in grams of the $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$ required to achieve 12 ppm of iron in 150 kg of wheat is _______ (Nearest integer).} (Given : Molar mass of $\mathrm{Fe}, \mathrm{S}$ and O respectively are 56,32 and $16 \mathrm{~g} \mathrm{~mol}^{-1}$ )
Figure 8.9 shows the strain-stress curve for a given material. What are (a) Young’s modulus and (b) approximate yield strength for this material?

Two identical ball bearings in contact with each other and resting on a frictionless table are hit head-on by another ball bearing of the same mass moving initially with a speed V. If the collision is elastic, which of the following (Fig. 5.14) is a possible result after collision ?
