How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 100 cm and 144 cm
(b) 70 cm and 36 cm.
(a) 100 cm and 144 cm
(b) 70 cm and 36 cm.
Approach Solution - 1
(a) Area of region = 100 cm x 144 cm = 14400 cm2
Area of one tile = 5 cm x 12 cm = 60 cm2
Number of tiles = Area of region Area of one tile
= 14400 60 = 240
Thus, 240 tiles are required.
(b) Area of region = 70 cm x 36 cm = 2520 cm2
Area of one tile = 5 cm x 12 cm = 60 cm2
Number of tiles = Area of region Area of one tile
= 2520 60 = 42
Thus, 42 tiles are required.
Approach Solution -2
Given that the length and breadth of the tiles are 12 cm and 5 cm respectively. Hence, the area of the tiles is calculated by multiplying the length and breadth, which equals 12 cm × 5 cm = 60 cm².
Now, for (a) a rectangular region with dimensions 100 cm and 144 cm: The area of the region is found by multiplying the length and breadth, resulting in 14,400 cm².
Therefore, the number of tiles needed is 14,400 ÷ 60 = 240 tiles.
For (b) a rectangular region with dimensions 70 cm and 36 cm: The area of the region is calculated by multiplying the length and breadth, yielding 70 cm × 36 cm = 2520 cm².
Thus, the required number of tiles is 2520 ÷ 60 = 42 tiles.
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