Question:

How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: 
(a) 100 cm and 144 cm 
(b) 70 cm and 36 cm.

Updated On: Jun 7, 2024
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Approach Solution - 1

(a) Area of region = 100 cm x 144 cm = 14400 cm
Area of one tile = 5 cm x 12 cm = 60 cm
Number of tiles = Area of region Area of one tile 
= 14400 60 = 240

Thus, 240 tiles are required. 


(b) Area of region = 70 cm x 36 cm = 2520 cm
Area of one tile = 5 cm x 12 cm = 60 cm
Number of tiles = Area of region Area of one tile 
= 2520 60 = 42

Thus, 42 tiles are required. 

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Approach Solution -2

Given that the length and breadth of the tiles are 12 cm and 5 cm respectively. Hence, the area of the tiles is calculated by multiplying the length and breadth, which equals 12 cm × 5 cm = 60 cm².

Now, for (a) a rectangular region with dimensions 100 cm and 144 cm: The area of the region is found by multiplying the length and breadth, resulting in 14,400 cm². 
Therefore, the number of tiles needed is 14,400 ÷ 60 = 240 tiles.

For (b) a rectangular region with dimensions 70 cm and 36 cm: The area of the region is calculated by multiplying the length and breadth, yielding 70 cm × 36 cm = 2520 cm². 
Thus, the required number of tiles is 2520 ÷ 60 = 42 tiles.

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