Question:

How many qualified in both Maths and LR but not any other subjects?

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For “\(A\) and \(B\) but not others,” subtract the triple intersections that include \(A\) and \(B\) from \(|A\cap B|\).
Updated On: Aug 18, 2025
  • 5
  • 10
  • 15
  • 20
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The Correct Option is B

Solution and Explanation


Exactly \(M\cap L\) only (excluding \(D\) and \(E\)) equals \[ |M\cap L| - |M\cap L\cap E| - |D\cap M\cap L| = 20-5-5=10. \] \[ \boxed{10} \]
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