Step 1: General approach.
Primary amines have –NH$_2$ group attached to an alkyl chain. We need to find all possible structural isomers for C$_4$H$_{11}$N.
Step 2: Possible structures.
1. n-Butylamine: CH$_3$–CH$_2$–CH$_2$–CH$_2$–NH$_2$
2. sec-Butylamine: CH$_3$–CH(NH$_2$)–CH$_2$–CH$_3$
3. Isobutylamine: (CH$_3$)$_2$CH–CH$_2$–NH$_2$
4. tert-Butylamine: (CH$_3$)$_3$C–NH$_2$
Step 3: Conclude.
Total = 4 primary amines.
Final Answer:
\[
\boxed{4}
\]
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