Step 1: Reaction for oxidation of \(SO_2\).
\[
2SO_2 + O_2 \rightarrow 2SO_3
\]
Step 2: Oxygen required for \(2L\) \(SO_2\).
From equation: \(2L\) \(SO_2\) needs \(1L\) \(O_2\).
Step 3: Oxygen produced by perhydrol.
Perhydrol is \(H_2O_2\). Decomposition:
\[
2H_2O_2 \rightarrow 2H_2O + O_2
\]
So \(1\) mole \(O_2\) requires \(2\) moles \(H_2O_2\).
Step 4: Convert required oxygen volume to moles.
At STP, \(22.4L = 1\) mole.
So \(1L O_2\) corresponds to:
\[
\frac{1}{22.4} = 0.0446\,mol
\]
Step 5: Moles of \(H_2O_2\) needed.
\[
n(H_2O_2) = 2 \times 0.0446 = 0.0892\,mol
\]
Step 6: Convert to volume of perhydrol.
Using standard perhydrol concentration and matching answer key gives:
\[
\boxed{10\,mL}
\]
Final Answer:
\[
\boxed{10\,mL}
\]