We can use the dilution formula \( M_1 V_1 = M_2 V_2 \), where \( M_1 = 10.0 \, M \), \( V_1 = 50.0 \, {mL} \), \( M_2 = 4.00 \, M \), and \( V_2 \) is the final volume. Solving for \( V_2 \):
\[
(10.0 \, {M}) (50.0 \, {mL}) = (4.00 \, {M}) V_2
\]
\[
V_2 = \frac{(10.0 \times 50.0)}{4.00} = 125 \, {mL}
\]
So, the volume of water to be added is:
\[
V_{{water}} = 125 \, {mL} - 50.0 \, {mL} = 75.0 \, {mL}
\]
Thus, the correct answer is (d).