Question

How many grams of Mg is required to completely reduce 100 mL, 0.1 M $\mathrm{NO}_3^-$ solution using the following reaction? $\mathrm{NO}_3^- + \mathrm{Mg} \to \mathrm{Mg}^{2+} + \mathrm{NH}_3$

• A. $0.96$
• B. $0.62$
• C. $0.24$
• D. $0.75$

Hint:

Use mole concept and stoichiometry for redox reaction calculations.

Answer 1

The Correct Option is A

Moles of $\mathrm{NO}_3^-$ = $0.1 \times 0.1 = 0.01$ mol
Mg reacts in stoichiometric ratio with $\mathrm{NO}_3^-$, calculate mass = moles $\times$ molar mass