Sum of all disjoint regions computed above:
Inside \(E\): \(10+25+10+5=50\).
Outside \(E\): \(\text{Only }M=10,\ \text{Only }L=8,\ \text{Only }D=17,\ ML\text{-only}=10,\ DML=5\) giving \(50\).
Total accounted \(=50+50=100\) (all aspirants). Hence outside all sections \(=0\). Since \(0\) is not among (a)–(c), answer is “None of these.â€
\[
\boxed{0}
\]