\( H_2O \rightarrow H_2 + \frac{1}{2}O_2 \)
1 mole \( H_2O \rightarrow \) 2 Faradays = \( 2 \times 96500 \, \text{C} \)
0.1 mole \( H_2O \rightarrow x \, \text{C} \)
\( x = \frac{2 \times 96500 \times 0.1}{1} = 19300 \, \text{C} = 1.93 \times 10^4 \, \text{C} \)