According to the universal law of gravitation, gravitational force (\(F\)) acting between two objects is inversely proportional to the square of the distance (\(r\)) between them, i.e.,
\(๐นโ \frac{1 }{๐^2 }\)
If distance r becomes \(\frac{r}2\), then the gravitational force will be proportional to
\(\frac1{ (\frac๐{2})^2}\) = \(\frac4{๐^2}\)
Hence, if the distance is reduced to half, then the gravitational force becomes four times larger than the previous value.
Net gravitational force at the center of a square is found to be \( F_1 \) when four particles having masses \( M, 2M, 3M \) and \( 4M \) are placed at the four corners of the square as shown in figure, and it is \( F_2 \) when the positions of \( 3M \) and \( 4M \) are interchanged. The ratio \( \dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is 

(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and โ DAB = โ CBA (see Fig. 7.17). Prove that
(i) โ ABD โ โ BAC
(ii) BD = AC
(iii) โ ABD = โ BAC.
