To solve the problem, we need to identify which of the given complexes are homoleptic. A homoleptic complex is defined as a coordination compound in which all the ligands are identical.
1. Understanding Homoleptic Complexes:
A homoleptic complex has only one type of ligand coordinated to the central metal ion. For example:
- $ \text{[Co(NH}_3\text{)}_6\text{]Cl}_3 $ is homoleptic because all ligands are $ \text{NH}_3 $.
- $ \text{[Co(NH}_3\text{)}_4\text{(H}_2\text{O)}_2\text{]}^{2+} $ is not homoleptic because it has two different ligands: $ \text{NH}_3 $ and $ \text{H}_2\text{O} $.
2. Analyzing Each Option:
(A) $ \text{K}_3\text{[Al(C}_2\text{O}_4\text{)}_3\text{]} $:
- The central metal ion is $ \text{Al}^{3+} $.
- The ligand is $ \text{C}_2\text{O}_4^{2-} $ (oxalate ion).
- All three ligands are identical ($ \text{C}_2\text{O}_4^{2-} $).
- Therefore, this is a homoleptic complex.
(B) $ \text{[CoCl}_2\text{(en)}_2\text{]}^+ $:
- The central metal ion is $ \text{Co}^{3+} $.
- The ligands are $ \text{Cl}^- $ and $ \text{en} $ (ethylenediamine, $ \text{H}_2\text{NCH}_2\text{CH}_2\text{NH}_2 $).
- There are two different types of ligands: $ \text{Cl}^- $ and $ \text{en} $.
- Therefore, this is not a homoleptic complex.
(C) $ \text{K}_2\text{[Zn(OH)}_4\text{]} $:
- The central metal ion is $ \text{Zn}^{2+} $.
- The ligand is $ \text{OH}^- $.
- All four ligands are identical ($ \text{OH}^- $).
- Therefore, this is a homoleptic complex.
3. Identifying the Correct Answer:
- From the analysis:
- Option (A) is homoleptic.
- Option (B) is not homoleptic.
- Option (C) is homoleptic.
- The correct answer includes options (A) and (C).
Final Answer:
The correct answer is $ \text{(A) and (C) only} $.
A homoleptic complex is a coordination compound that contains only one type of ligand. Now let's analyze each option:
Thus, the homoleptic complexes are (A) and (C), making option (C) the correct answer.
The correct answer is (C) : (A) and (C) only.