Heavier coins are more valuable.
Ram's coin is heavier than Mohan's coin and more valuable than Ramesh's coin.
Naresh's coin is more valuable than Ram's coin and costlier than Yogesh's coin.
The order of value is:
Show Hint
When solving logical ordering problems, break down each relationship step by step and verify the final order against the given options.
Step 1: Understand the Problem. We are given the following information: (A) Ram's coin is heavier than Mohan's coin and more valuable than Ramesh's coin. (B) Naresh's coin is more valuable than Ram's coin and costlier than Yogesh's coin. Since heavier coins are more valuable, we can infer that the order of value is directly related to the order of weight. Step 2: Establish the Order of Value. From the given information: Ram \(>\) Ramesh (Ram's coin is more valuable than Ramesh's coin). Naresh \(>\) Ram (Naresh's coin is more valuable than Ram's coin). Ram>Mohan (Ram's coin is heavier and thus more valuable than Mohan's coin). Naresh>Yogesh (Naresh's coin is costlier and thus more valuable than Yogesh's coin). Combining these relationships: \[ \text{Naresh \(>\) Ram \(>\) Ramesh \(>\) Mohan \(>\) Yogesh} \] Step 3: Match with the Options. Now, let's match this order with the given options: Option A: Yogesh \(<\) Naresh \(>\) Ram \(>\) Ramesh/Mohan This matches our derived order. Naresh is the most valuable, followed by Ram, and Ramesh/Mohan are less valuable than Ram. Yogesh is the least valuable. Option B: Yogesh \(>\) Ram \(>\) Naresh \(>\) Ramesh \(>\) Mohan Incorrect because Yogesh cannot be more valuable than Ram or Naresh. Option C: Mohan / Ramesh \(>\) Naresh \(>\) Yogesh / Ram Incorrect because it does not establish a clear linear order and misplaces Yogesh. Option D: Mohan \(>\) Ramesh \(>\) Ram \(>\) Naresh \(>\) Yogesh Incorrect because Naresh is more valuable than Ram, not the other way aroun(D) The correct order is: \[ \text{Yogesh \(<\) Naresh \(>\) Ram \(>\) Ramesh/Mohan} \]
