Question:

Gold and copper are as heavy as water by 19 and 9 times respectively. The ratio in which these two metals be mixed so that the mixture is 17 times as heavy as water is ..............

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For mixture problems with specific gravities, alligation is the fastest method — always take the heavier element first in subtraction to avoid sign confusion.
Updated On: Aug 14, 2025
  • 3:2
  • 4:1
  • 2:3
  • 3:4
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The Correct Option is B

Solution and Explanation

We are given relative densities (specific gravities): Gold = 19, Copper = 9, and Mixture = 17.
This is a classic alligation problem, where we use the formula: \[ \text{Ratio of quantities} = (\text{Difference between first and mean}) : (\text{Difference between mean and second}) \] For gold and copper: Difference between gold and mixture = \( 19 - 17 = 2 \).
Difference between mixture and copper = \( 17 - 9 = 8 \).
Thus, the ratio = \( 8 : 2 = 4 : 1 \).
So gold and copper should be mixed in the ratio 4:1 by weight.
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