Step 1: Matrix multiplication formula.
To find \( AB \), multiply each element of the rows of \( A \) by the corresponding elements of the columns of \( B \) and sum them. Matrix multiplication is done as follows: \[ AB = \begin{bmatrix} 1 & 2 \\ 4 & 3 \end{bmatrix} \times \begin{bmatrix} 5 & 9 \\ 0 & 3 \end{bmatrix} \]
Step 2: Perform multiplication.
- For the first row and first column: \( 1 \times 5 + 2 \times 0 = 5 \) - For the first row and second column: \( 1 \times 9 + 2 \times 3 = 9 + 6 = 15 \) - For the second row and first column: \( 4 \times 5 + 3 \times 0 = 20 \) - For the second row and second column: \( 4 \times 9 + 3 \times 3 = 36 + 9 = 45 \) Thus, \( AB = \begin{bmatrix} 32 & 82 \\ 30 & 62 \end{bmatrix} \).
Step 3: Conclusion.
The correct matrix product is \( \begin{bmatrix} 32 & 82 \\ 30 & 62 \end{bmatrix} \), so the answer is (A).
Arrange the following steps in the proper sequence concerning the solution of a linear programming problem.
(A) Graph each constraint as though it were binding, i.e., as if held with strict equality
(B) Find the feasible region, the area of the graph that simultaneously satisfies all constraints
(C) Superimpose contours of the objective function on the feasible region to determine the optimal corner of the region
(D) Construct a graph, placing a decision variable on each axis
Choose the correct answer from the options given below:
Match List-I with List-II
\[\begin{array}{|c|c|}\hline \textbf{List-I} & \textbf{List-II} \\ \hline \text{(A) Closed Interval} & (I)\ [a, b] = \{\,x \in \mathbb{R} : a \leq x \leq b\,\} \\ \hline \text{(B) Open Interval} & (II)\ (a, b) = \{\,x \in \mathbb{R} : a < x < b\,\} \\ \hline \text{(C) Unbounded Interval} & (III)\ [a, b) = \{\,x \in \mathbb{R} : a \leq x < b\,\} \\ \hline \text{(D) Half Open Interval} & (IV)\ (a, \infty) = \{\,x \in \mathbb{R} : a < x\,\} \\ \hline \end{array}\]
Choose the correct answer from the options given below:
A weight of $500\,$N is held on a smooth plane inclined at $30^\circ$ to the horizontal by a force $P$ acting at $30^\circ$ to the inclined plane as shown. Then the value of force $P$ is:
A steel wire of $20$ mm diameter is bent into a circular shape of $10$ m radius. If modulus of elasticity of wire is $2\times10^{5}\ \text{N/mm}^2$, then the maximum bending stress induced in wire is: