Question:
Given: P(A) = 0.35, P(B) = 0.25.
A and B are mutually exclusive.
Find P(A ∪ B) (round to 3 decimals).
Given: P(A) = 0.35, P(B) = 0.25.
A and B are mutually exclusive.
Find P(A ∪ B) (round to 3 decimals).
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Mutually exclusive ⇒ P(A ∩ B) = 0 ⇒ union is just sum.
Updated On: Dec 22, 2025
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Correct Answer: 0.583
Solution and Explanation
For mutually exclusive events:
\[
P(A \cup B) = P(A) + P(B)
\]
\[
= 0.35 + 0.25 = 0.60
\]
Thus,
\[
\boxed{0.600}
\]
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