Question:

Given:
\(E\degree_{K^+/K}=-2.93V,\)
\(E\degree_{Ag^+/Ag}=0.80V,\)
\(E\degree_{Hg^{2+}/Hg}=0.79V,\)
\(E\degree_{Mg^{2+}/Mg}=-2.37V,\)
\(E\degree_{Cr^{3+}/Cr}=-0.74V,\)
Choose the correct order :
(A) Ag <Hg< Cr <Mg <K (increasing reducing power)
(B) Ag <Hg< Cr <Mg <K (decreasing oxidising power)
(C) Ag > Hg > Cr > Mg > K (decreasing oxidising power)
(D) Hg > Cr > Ag > K > Mg (increasing reactivity)
(E) K > Mg > Cr > Hg > Ag (decreasing reactivity order)
Choose the correct answer from the options given below:

Updated On: May 21, 2024
  • (A), (C) and (E) only
  • (B), (C) and (E) only
  • (C), (D) and (E) only
  • (A) and (B) only
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The Correct Option is A

Solution and Explanation

The correct option is (A) : (A), (C) and (E) only
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