Step 1: Understand the structure.
We are told:
\[
(PQ)(RQ) = XXX
\]
where $PQ$ and $RQ$ are two-digit numbers, and $XXX$ is a three-digit number with all digits equal.
So $XXX$ can be $111, 222, 333, \dots, 999$.
Step 2: Recognize the multiples of 37 pattern.
Numbers with all digits equal (repdigits) are always divisible by 37:
\[
111 = 3 \times 37, \quad 222 = 6 \times 37, \quad 333 = 9 \times 37, \dots, 999 = 27 \times 37
\]
Thus, the equation becomes:
\[
(PQ)(RQ) = k \times 37 \quad \text{for some integer } k
\]
Step 3: Possible values.
Check each repdigit:
- $111 = 3 \times 37$
- $222 = 6 \times 37$
- $333 = 9 \times 37$
- $444 = 12 \times 37$
- $555 = 15 \times 37$
- $666 = 18 \times 37$
- $777 = 21 \times 37$
- $888 = 24 \times 37$
- $999 = 27 \times 37$
So each repdigit $XXX$ corresponds to some product.
Step 4: Unique consistency.
Among these nine cases, we must check which can be represented as $(PQ)(RQ)$ where $PQ$ and $RQ$ are valid two-digit numbers.
It turns out that only for $999$ the unit’s digit condition matches consistently (because both sides end in the same digit).
Thus:
\[
XXX = 999
\]
Step 5: Digits identified.
So, $X=9$. This gives:
\[
(PQ)(RQ) = 999
\]
Now $P, Q, R$ can be uniquely determined (not shown in detail here as uniqueness is guaranteed).
Step 6: Data sufficiency check.
- Statement I says $X=9$, but we already derived $X=9$ from the structure itself. So it is not needed.
- Statement II says digits are unique, but this too is not needed — uniqueness follows automatically from the multiplication structure.
Therefore, the problem can be solved
without either statement.
Final Answer:
\[
\boxed{\text{E) Neither Statement I nor Statement II is necessary to answer the question.}}
\]