Question:

Given below are two statements: Statement I: The correct order for radius is \( \text{Al}>\text{Mg}>\text{Mg}^{2+}>\text{Al}^{3+} \). Statement II: Atomic size always depends on electronegativity. In the light of the above statements, choose the correct option.

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When comparing atomic sizes, remember that cations are always smaller than their parent atoms, and anions are larger. The size also depends on nuclear charge and electron shielding.
Updated On: Jan 23, 2026
  • Both Statement I and Statement II are correct
  • Both Statement I and Statement II are incorrect
  • Statement I is correct but Statement II is incorrect
  • Statement I is incorrect but Statement II is correct
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The Correct Option is C

Solution and Explanation

Step 1: Analyzing Statement I.
The given order for radii is \( \text{Al}>\text{Mg}>\text{Mg}^{2+}>\text{Al}^{3+} \). This order is correct because: - \( \text{Al} \) (atomic radius of aluminum) is larger than \( \text{Mg} \) (atomic radius of magnesium) due to fewer protons in Al's nucleus compared to Mg. - \( \text{Mg}^{2+} \) (Mg ion) has a smaller radius than Mg due to the loss of electrons and increased nuclear attraction. - \( \text{Al}^{3+} \) (Al ion) has the smallest radius due to the even higher nuclear charge and fewer electrons. So, Statement I is correct.
Step 2: Analyzing Statement II.
Statement II says atomic size always depends on electronegativity. However, atomic size primarily depends on factors like nuclear charge, electron shielding, and quantum levels, rather than just electronegativity. Therefore, Statement II is incorrect. Thus, the correct answer is (3).
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