Statement I: The Balmer series corresponds to electronic transitions where the electron falls to the n=2 energy level. The lowest energy transition in the Balmer series is from n=3 to n=2. The wavenumber ($\tilde{\nu}$) for this transition can be calculated using the Rydberg formula:
\[ \tilde{\nu} = R_\text{H} \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \]
For the lowest energy Balmer transition ($n_1$=2, $n_2$=3):
\[ \tilde{\nu} = R_H \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = R_H \left( \frac{1}{4} - \frac{1}{9} \right) = R_H \left( \frac{9 - 4}{36} \right) = \frac{5}{36} R_H \]
The wavenumber is indeed $\frac{5}{36} R_H$ cm$^{-1}$. Thus, statement I is true.
Statement II: Wien's displacement law states that the wavelength of maximum intensity for blackbody radiation is inversely proportional to its temperature. As the temperature increases, the wavelength of maximum intensity shifts to shorter wavelengths. Thus, statement II is true.
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :