Question:

Given below are two statements : Statement I : Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame. Statement II : Cuprous metaborate is obtained by heating boric anhydride and copper sulphate in a non-luminous flame. In the light of the above statements, choose the most appropriate answer from the options given below.

Updated On: Aug 14, 2024
  • Statement I is true but Statement II is false
  • Both Statement I and Statement II are false
  • Statement I is false but Statement II is true
  • Both Statement I and Statement II are true
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The Correct Option is B

Solution and Explanation

(i) Blue cupric metaborate is reduced to colourless cuprous metaborate in a luminous flame




(ii) Cupric metaborate is obtained by heating boric anhydride and copper sulphate in a non luminous flame.

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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: