Given below are two statements : Statement I: A savings account at Bank A pays 6.2% interest, compounded annually. Bank B's savings account pays 6% compounded semi-annually. Bank B is paying less total interest each year. Statement II: A sum of money at a certain rate of compound interest doubles in 3 years. In 9 years, it will be P times original principal. Then P = 9. In the light of the above statements, choose the correct answer from the options given below.
To evaluate the given statements, we will analyze each one step-by-step:
Statement I: A savings account at Bank A pays 6.2% interest, compounded annually. Bank B's savings account pays 6% compounded semi-annually. Bank B is paying less total interest each year.
We first need to calculate the effective annual rate (EAR) for each bank, as the compounding frequencies differ.
For Bank A, which compounds annually at 6.2%, the effective interest rate remains 6.2%.
For Bank B, the semi-annual compounding requires the following formula to determine the EAR:
The formula for EAR is: \(EAR = \left(1 + \frac{r}{n}\right)^n - 1\) where \(r\) is the nominal rate and \(n\) is the number of compounding periods.
Here, \(r = 6\%\) and \(n = 2\) (because of the semi-annual compounding).
Plugging in the values, we get:
Since Bank A offers 6.2% and Bank B effectively offers 6.09%, Bank B pays less interest, making Statement I true.
Statement II: A sum of money at a certain rate of compound interest doubles in 3 years. In 9 years, it will be P times the original principal. Then P = 9.
The formula for compound interest is given by: \(A = P \times (1 + r)^t\) where \(A\) is the amount of money, \(P\) is the principal, \(r\) is the rate, and \(t\) is the number of years.
Given that the principal doubles in 3 years, the relationship is:
Solving for \(1 + r\) gives:
After 9 years, the amount becomes:
Hence, the principal is multiplied by 8, not 9, making Statement II false.
Based on these analyses, the correct answer is that Statement I is true but Statement II is false.