To solve the given assertion and reason problem, we first need to analyze the statements individually and then collectively:
Therefore, the correct answer is: Both (A) and (R) are correct and (R) is the correct explanation of (A).
Step 1: Analyze Assertion (A).
Assertion (A) states Kepler's second law of planetary motion: the radius vector from the Sun to a planet sweeps out equal areas in equal intervals of time, implying constant areal velocity. This is a fundamental law of planetary motion and is correct.
Step 2: Analyze Reason (R).
Reason (R) states that for a central force field, the angular momentum is a constant. Gravitational force, which governs planetary motion around the Sun, is a central force. Under a central force, the torque on the planet with respect to the Sun is zero, leading to the conservation of the planet's angular momentum.
Thus, Reason (R) is also correct.
Step 3: Determine if Reason (R) is the correct explanation of Assertion (A).
The areal velocity \( \frac{dA}{dt} \) of a planet is mathematically related to its angular momentum \( L \) by \( \frac{dA}{dt} = \frac{L}{2m} \), where \( m \) is the mass of the planet. Since the gravitational force is central, the angular momentum \( L \) is conserved. As the mass \( m \) is also constant, the areal velocity \( \frac{dA}{dt} \) remains constant.
Therefore, the conservation of angular momentum (Reason (R)) directly explains the constant areal velocity (Assertion (A)).
A small point of mass \(m\) is placed at a distance \(2R\) from the center \(O\) of a big uniform solid sphere of mass \(M\) and radius \(R\). The gravitational force on \(m\) due to \(M\) is \(F_1\). A spherical part of radius \(R/3\) is removed from the big sphere as shown in the figure, and the gravitational force on \(m\) due to the remaining part of \(M\) is found to be \(F_2\). The value of the ratio \( F_1 : F_2 \) is: 
Match the LIST-I with LIST-II
\[ \begin{array}{|l|l|} \hline \text{LIST-I} & \text{LIST-II} \\ \hline \text{A. Gravitational constant} & \text{I. } [LT^{-2}] \\ \hline \text{B. Gravitational potential energy} & \text{II. } [L^2T^{-2}] \\ \hline \text{C. Gravitational potential} & \text{III. } [ML^2T^{-2}] \\ \hline \text{D. Acceleration due to gravity} & \text{IV. } [M^{-1}L^3T^{-2}] \\ \hline \end{array} \]
Choose the correct answer from the options given below:
In the experiment for measurement of viscosity \( \eta \) of a given liquid with a ball having radius \( R \), consider following statements:
A. Graph between terminal velocity \( V \) and \( R \) will be a parabola.
B. The terminal velocities of different diameter balls are constant for a given liquid.
C. Measurement of terminal velocity is dependent on the temperature.
D. This experiment can be utilized to assess the density of a given liquid.
E. If balls are dropped with some initial speed, the value of \( \eta \) will change.
Given below are two statements: one is labelled as Assertion \(A\) and the other as Reason \(R\):
Assertion \(A\): A sound wave has higher speed in solids than in gases.
Reason \(R\): Gases have higher value of Bulk modulus than solids.
A bead of mass \( m \) slides without friction on the wall of a vertical circular hoop of radius \( R \) as shown in figure. The bead moves under the combined action of gravity and a massless spring \( k \) attached to the bottom of the hoop. The equilibrium length of the spring is \( R \). If the bead is released from the top of the hoop with (negligible) zero initial speed, the velocity of the bead, when the length of spring becomes \( R \), would be (spring constant is \( k \), \( g \) is acceleration due to gravity): 