The given complex is \( [\text{Pt(NH}_3\text{)}_4][\text{PtCl}_4] \), which is made up of two parts:
The first part \( [\text{Pt(NH}_3\text{)}_4] \) involves a platinum (II) ion coordinated to four ammine (\( \text{NH}_3 \)) ligands. The ammine is neutral and the platinum is in the \( +2 \) oxidation state.
The second part \( [\text{PtCl}_4] \) involves a platinum ion coordinated to four chloride (\( \text{Cl}^- \)) ligands, where platinum is in the \( +4 \) oxidation state.
Thus, the correct IUPAC name involves: The first part, \( [\text{Pt(NH}_3\text{)}_4] \), is named "tetra ammine platinate (0)" since platinum is in the \( +2 \) oxidation state, making it a platinate (0) complex. - The second part, \( [\text{PtCl}_4] \), is named "tetra chlorido platinum (IV)" since platinum is in the \( +4 \) oxidation state.
Thus, the IUPAC name is "tetra ammine platinate (0) tetra chlorido platinum (IV)".
The complex ion \( [\text{Pt(NH}_3)_4]^{2+} \) consists of platinum in the +2 oxidation state and four ammine (NH₃) ligands. The other complex ion \( [\text{PtCl}_4]^{2-} \) consists of platinum in the +4 oxidation state and four chlorido (Cl⁻) ligands. The IUPAC naming for such complexes is based on the oxidation states of the central metal atoms. For this compound: - The ammine ligand is denoted as "ammine."
The chlorido ligand is denoted as "chlorido."
The oxidation state of platinum in the first complex is +2, and in the second complex, it is +4.
Thus, the correct IUPAC name is "tetra ammine platinat (0) tetra chlorido platinum (IV)."
Hence, the correct answer is (D).
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2
Nomenclature of Coordination Compounds is important in Coordination Chemistry because of the need to have an unambiguous method of describing formulas and writing systematic names, particularly when dealing with isomers.