Question:
From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of distances covered by it in the 3rd and 2nd seconds of its motion is (Take g = $10 m/s^2$)
From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of distances covered by it in the 3rd and 2nd seconds of its motion is (Take g = $10 m/s^2$)
Updated On: Jul 6, 2022
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The Correct Option is B
Solution and Explanation
$s_{3rd}=10+\frac{10}{2}(2 \times 3 -1 )=35 m$
$s_{2nd}=10+\frac{10}{2}(2 \times 2-1 )=25 m$
$\Rightarrow$ $\frac{s_{2nd}}{s_{3rd}}=\frac{7}{5}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.