Question:

Four girls (G$_1$, G$_2$, G$_3$, G$_4$) and three boys (B$_1$, B$_2$, B$_3$) are to sit for a dinner such that no two boys should sit together nor two girls. If they are successively sitting, what is the position of B$_2$ and G$_3$?

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For problems with boys and girls not sitting together, always form an alternating sequence. Start with the majority group and place the others in between.
Updated On: Aug 20, 2025
  • 5th and 6th
  • 4th and 5th
  • 3rd and 4th
  • 2nd and 3rd
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The Correct Option is B

Solution and Explanation

Step 1: Apply the condition.
There are 4 girls and 3 boys. Since boys cannot sit together and girls cannot sit together, the only possible seating is alternating. Because there are more girls, the sequence must start and end with a girl. \[ \text{Pattern: G – B – G – B – G – B – G} \] Step 2: Assign positions.
- Position 1: G$_1$ - Position 2: B$_1$ - Position 3: G$_2$ - Position 4: B$_2$ - Position 5: G$_3$ - Position 6: B$_3$ - Position 7: G$_4$ Step 3: Identify the required positions.
- B$_2$ is at position 4. - G$_3$ is at position 5. \[ \boxed{\text{(b) 4th and 5th}} \]
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