Question

Force on a current-carrying conductor placed in a magnetic field is given by:

• A. \( BIl \sin \theta \) Newtons
• B. \( BIl \cos \theta \) Newtons
• C. \( BIl \sin(\theta + 45^\circ) \) Newtons
• D. \( BIl \cos(\theta + 45^\circ) \) Newtons

Hint:

Remember: Maximum force occurs when conductor is perpendicular to the magnetic field (\(\theta = 90^\circ\)).

Answer 1

The Correct Option is A

The magnetic force on a straight current-carrying conductor is given by: \[ F = BIl \sin \theta \] Where: - \(B\) = magnetic field,
- \(I\) = current,
- \(l\) = length of conductor,
- \(\theta\) = angle between conductor and field.