Question:

For the square planar complex $[M(a)(b)(c)(d)]$ (where, $M =$ central metal and $a, b, c$ and $d$ are monodentate ligands), the number of possible geometrical isomers are

Updated On: Jul 12, 2022
  • 1
  • 2
  • 3
  • 4
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

For $[M [a][b][c][d]]$ square planar complex, the number of possible geometrical isomers is three which is obtained by fixing the position of one of the ligands say $a$ while the other ligands $b, c$ and $d$ are placed trans to it.
Was this answer helpful?
0
0

Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.