Step 1: Coordination Numbers of Transition Elements.
Transition metals, especially in the second and third periods, commonly form complexes with high coordination numbers due to their relatively large size and ability to accommodate multiple ligands. Hence, they do not typically show low coordination numbers.
Step 2: Analyzing the Options.
- (1) The statement "The metals commonly show lower coordination number" is not true for the second and third row transition metals. They tend to have higher coordination numbers.
- (2) Binuclear carboxylate complexes are common for transition metals.
- (3) Many halides of transition elements are indeed cluster compounds, especially in higher oxidation states.
- (4) Transition metals can form carbonyl complexes with metal-metal bonds, such as in dicobalt octacarbonyl.
Step 3: Conclusion.
Thus, the incorrect statement is (1), so the correct answer is option (1).
Give explanation for each of the following observations:
(a) With the same d-orbital configuration (d4), Mn3+ ion is an oxidizing agent whereas Cr2+ ion is a reducing agent.
(b) Actinoid contraction is greater from element to element than that among lanthanoids.
(c) Transition metals form a large number of interstitial compounds with H, B, C, and N.
A transition metal (M) among Mn, Cr, Co, and Fe has the highest standard electrode potential $ M^{n}/M^{n+1} $. It forms a metal complex of the type $[M \text{CN}]^{n+}$. The number of electrons present in the $ e $-orbital of the complex is ... ...
A weight of $500\,$N is held on a smooth plane inclined at $30^\circ$ to the horizontal by a force $P$ acting at $30^\circ$ to the inclined plane as shown. Then the value of force $P$ is:
A steel wire of $20$ mm diameter is bent into a circular shape of $10$ m radius. If modulus of elasticity of wire is $2\times10^{5}\ \text{N/mm}^2$, then the maximum bending stress induced in wire is: