Question:

For the resistance network shown in the figure, choose the correct option(s).

Updated On: Jun 23, 2023
  • The current through $PQ$ is zero
  • $I_1=3A$
  • The potential at $S$ is less than that at $Q$
  • $I_2=2A$
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The Correct Option is D

Solution and Explanation

Due to symmetry on upper side and lower side, points P and Q are at same potentials. Similarly, points S and T are at same potentials.
Therefore, the simple circuit can be drawn as shown below
$I_2=\frac{12}{2+2+2}=2A$
$I_3=\frac{12}{4+4+4}=1A$
$\therefore I_1=I_2+I_3=3A$
$I_{PQ}=0$ because $V_P=V_Q$
Potential drop (from left to right) across each resistance is
$\frac{12}{3}=4V$
$\therefore V_{MS}=2\times4=8V$
$V_{NQ}=1\times4=4V$
or $V_S< V_Q$
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Concepts Used:

Current Electricity

Current electricity is defined as the flow of electrons from one section of the circuit to another.

Types of Current Electricity

There are two types of current electricity as follows:

Direct Current

The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.

Alternating Current

The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.