Question:
For the given radioactive decay \(^{298}_{94}X → ^{294}_{92}X + ^{4}_{2}ɑ + Q\) - value, binding energy per nucleon of X, Y and ɑ are a, b and c. The Q - value is equal to
For the given radioactive decay \(^{298}_{94}X → ^{294}_{92}X + ^{4}_{2}ɑ + Q\) - value, binding energy per nucleon of X, Y and ɑ are a, b and c. The Q - value is equal to
Updated On: Sep 14, 2024
- 294b + 4c - 298a
- 92b + 2c - 94a
- 92b + 2c - 94a
- 92b + 2c + 94a
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The Correct Option is A
Solution and Explanation
The correct option is (A): 294b + 4c - 298a
Q-value = (B.E)product-(B.E)reaction
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