Question:

For the complex ion \(\text{Mn}^{5+}\), what is the electronic configuration?

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For transition metal ions, count the number of electrons removed from the neutral atom to determine the electron configuration of the ion.
Updated On: Jan 20, 2026
  • Mn\(^5+\) : \( n = 5 \)
  • Fe\(^3+\) : \( n = 4 \)
  • Mn\(^2+\) : \( n = 4 \)
  • Cr\(^3+\) : \( n = 4 \)
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The Correct Option is A

Solution and Explanation


Step 1: Understanding the Ion.
The ion Mn\(^5+\) refers to a manganese ion with a +5 charge. The electronic configuration for Mn is [Ar] 3d\(^5\) 4s\(^2\), and when it loses 5 electrons to become Mn\(^5+\), it results in an electronic configuration that corresponds to \( n = 5 \).
Step 2: Conclusion.
The correct answer is (A) Mn\(^5+\) : \( n = 5 \).
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