For the chemical reaction, \(2\text{O}_3\rightleftharpoons 3\text{O}_2\), the reaction proceeds as follows:
\[\text{O}_3\rightleftharpoons \text{O}_2 + \text{O} \, \text{(fast)}\]
\[\text{O} + \text{O}_3 \rightarrow 2\text{O}_2 \, \text{(slow)}\]
The rate law expression will be: