For the chemical reaction, \(2\text{O}_3\rightleftharpoons 3\text{O}_2\), the reaction proceeds as follows: \[\text{O}_3\rightleftharpoons \text{O}_2 + \text{O} \, \text{(fast)}\] \[\text{O} + \text{O}_3 \rightarrow 2\text{O}_2 \, \text{(slow)}\] The rate law expression will be: