Step 1: Check if \( U(5) \) is cyclic.
The set \( U(5) = \{1, 2, 3, 4\} \) consists of numbers less than 5 that are coprime to 5. We check if there exists an element that can generate all elements of the set under multiplication modulo 5:
- \( 1^k \equiv 1 \pmod{5} \)
- \( 2^1 \equiv 2 \pmod{5}, \, 2^2 \equiv 4 \pmod{5}, \, 2^3 \equiv 3 \pmod{5}, \, 2^4 \equiv 1 \pmod{5} \)
- Hence, \( 2 \) is a generator, and \( U(5) \) is cyclic.
Step 2: Check \( U(8) \), \( U(12) \), and \( U(9) \).
We find that \( U(8) \) and \( U(12) \) are not cyclic based on their structure, and \( U(9) \) is not cyclic either.
Final Answer:
\[
\boxed{U(5) \text{ is a cyclic group.}}
\]