Question:

For \( n \in \mathbb{N} \), consider the set \( U(n) = \{ x \in \mathbb{Z}_n : \gcd(x, n) = 1 \} \) as a group under multiplication modulo \( n \). Then, which of the following is/are TRUE?

Show Hint

To determine if a group is cyclic, check if there exists an element that generates all the other elements of the group through repeated application of the group operation.
Updated On: Sep 6, 2025
  • \( U(8) \) is a cyclic group.
  • \( U(5) \) is a cyclic group.
  • \( U(12) \) is a cyclic group.
  • \( U(9) \) is a cyclic group.
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Check if \( U(5) \) is cyclic.
The set \( U(5) = \{1, 2, 3, 4\} \) consists of numbers less than 5 that are coprime to 5. We check if there exists an element that can generate all elements of the set under multiplication modulo 5: - \( 1^k \equiv 1 \pmod{5} \) - \( 2^1 \equiv 2 \pmod{5}, \, 2^2 \equiv 4 \pmod{5}, \, 2^3 \equiv 3 \pmod{5}, \, 2^4 \equiv 1 \pmod{5} \) - Hence, \( 2 \) is a generator, and \( U(5) \) is cyclic. Step 2: Check \( U(8) \), \( U(12) \), and \( U(9) \).
We find that \( U(8) \) and \( U(12) \) are not cyclic based on their structure, and \( U(9) \) is not cyclic either. Final Answer: \[ \boxed{U(5) \text{ is a cyclic group.}} \]
Was this answer helpful?
0
0

Top Questions on Calculus

View More Questions