Step 1: Binary search condition.
If the list is sorted in ascending order, the binary search compares the key with the middle element.
Step 2: Case analysis.
- If \texttt{mid__element == key}, key found at mid.
- If \texttt{mid__element>key}, key must be in the left half.
- If \texttt{mid__element<key}, key must be in the right half (second half).
Step 3: Apply condition.
Since middle element<key, the key lies in the second half.
Final Answer:
\[
\boxed{\text{The key is in the second half}}
\]