We are given a sequence where the first term is:
Next, we are told that:
\(x_1 - x_2 = 8\)
Substituting \(x_1 = 3\), we get:
\(3 - x_2 = 8 \Rightarrow x_2 = -5\)
Now using the next part of the series:
\(x_1 - x_2 + x_3 = 15\)
Substitute \(x_1 = 3\) and \(x_2 = -5\):
\(3 - (-5) + x_3 = 15 \Rightarrow 8 + x_3 = 15 \Rightarrow x_3 = 7\)
Now we try to identify the pattern of the sequence:
Observing the values of the terms:
\(x_1 = 3 = (+1)(2×1+1)\)
\(x_2 = -5 = (-1)(2×2+1)\)
\(x_3 = 7 = (+1)(2×3+1)\)
From this, we see that the general term of the sequence can be written as:
\(x_n = (-1)^{n+1}(2n+1)\)
Now, we calculate:
\(x_{49} = (-1)^{50}(2×49+1) = (-1)^{50}(99) = +99\)
\(x_{50} = (-1)^{51}(2×50+1) = (-1)^{51}(101) = -101\)
Therefore, the sum of these two terms is:
\(x_{49} + x_{50} = 99 + (-101) = -2\)
Given: The sum of the first n terms of a series is expressed by the formula:
\(S_n = x_1 - x_2 + x_3 - x_4 + \ldots + (-1)^{n+1} x_n = n^2 + 2n = n(n + 2)\)
This implies that the signs of the terms alternate: odd-positioned terms (e.g., \(x_1, x_3, x_5, \ldots\)) are positive, and even-positioned terms (e.g., \(x_2, x_4, x_6, \ldots\)) are negative.
To determine \(x_{49}\) and \(x_{50}\), we first calculate the values of:
From the recursive definition of the series:
To find \(x_{50}\):
\(S_{50} = S_{49} - x_{50} \Rightarrow x_{50} = S_{49} - S_{50} = 2499 - 2600 = -101\)
To find \(x_{49}\):
\(S_{49} = S_{48} + x_{49} \Rightarrow x_{49} = S_{49} - S_{48} = 2499 - 2400 = 99\)
Therefore, the sum of the 49th and 50th terms is:
\(x_{49} + x_{50} = 99 + (-101) = -2\)
Final Answer: \(-2\). Hence, the correct option is (B).
Which letter replaces the question mark? A, D, G, J, M, ?
When $10^{100}$ is divided by 7, the remainder is ?