Number of nuclei remaining $= 600 - 450 = 150$
$\frac{N}{N_{0}} = \left(\frac{1}{2}\right)^{n}$
$ \frac{150}{600} = \left(\frac{1}{2}\right)^{\frac{t}{t_{\frac{1}{2}}}}$
$ \left(\frac{1}{2}\right)^{2} = \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}$
$ t = 2t_{1/2} = 2 \times10 $
$ = 20 $ minute
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: