Question:

For a linear elastic and isotropic material, the correct relationship among Young's modulus of elasticity $(E)$, Poisson's ratio $(\nu)$, and shear modulus $(G)$ is:

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Remember that the shear modulus is related to the Young's modulus and Poisson's ratio for isotropic materials using the formula \( G = \dfrac{E}{2(1+\nu)} \).
Updated On: Dec 4, 2025
  • $G = \dfrac{E}{2(1+\nu)}$
  • $G = \dfrac{E}{(1+2\nu)}$
  • $E = \dfrac{G}{2(1+\nu)}$
  • $E = \dfrac{G}{(1+2\nu)}$
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The Correct Option is A

Solution and Explanation

For a linear elastic and isotropic material, the correct relationship between Young's modulus \(E\), Poisson's ratio \(\nu\), and shear modulus \(G\) is: \[ G = \dfrac{E}{2(1+\nu)} \] This relationship is derived from the equations that relate stress, strain, and material properties for isotropic materials. The correct option is (A).
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