Question:

For a flowing fluid, a dimensionless combination of velocity (V), length scale (l), and acceleration due to gravity (g) would be

Show Hint

When dealing with dimensionless quantities, always check the dimensional consistency of the equation to ensure that it is dimensionless.
Updated On: Apr 3, 2025
  • \( \frac{V^2}{gl} \)
  • \( \frac{Vg}{l} \)
  • \( \frac{g l^2}{V} \)
  • \( \frac{l}{V^2g} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

In fluid mechanics, dimensionless groups are often used to analyze the behavior of flowing fluids. 
The combination \( \frac{V^2}{gl} \) is a dimensionless number that describes the relationship between the velocity (\( V \)), length scale (\( l \)), and the acceleration due to gravity (\( g \)).

To check the dimensional correctness:

\[ \left[ \frac{V^2}{gl} \right] = \frac{\left[ {velocity} \right]^2}{\left[ {acceleration} \right] \times {length}} = \frac{\left( \frac{m}{s} \right)^2}{\left( \frac{m}{s^2} \right) \times m} = \frac{m^2/s^2}{m^2/s^2} = 1, \]

which confirms that the expression is dimensionless.

Therefore, the correct answer is option (A).

Other options do not form a dimensionless group, which is required for this problem.

Was this answer helpful?
0
0

Top Questions on Fluid Mechanics

View More Questions

Questions Asked in GATE CE exam

View More Questions