In fluid mechanics, dimensionless groups are often used to analyze the behavior of flowing fluids.
The combination \( \frac{V^2}{gl} \) is a dimensionless number that describes the relationship between the velocity (\( V \)), length scale (\( l \)), and the acceleration due to gravity (\( g \)).
To check the dimensional correctness:
\[ \left[ \frac{V^2}{gl} \right] = \frac{\left[ {velocity} \right]^2}{\left[ {acceleration} \right] \times {length}} = \frac{\left( \frac{m}{s} \right)^2}{\left( \frac{m}{s^2} \right) \times m} = \frac{m^2/s^2}{m^2/s^2} = 1, \]
which confirms that the expression is dimensionless.
Therefore, the correct answer is option (A).
Other options do not form a dimensionless group, which is required for this problem.
A flexible chain of mass $m$ is hanging as shown. Find tension at the lowest point. 

Consider a five-digit number PQRST that has distinct digits P, Q, R, S, and T, and satisfies the following conditions:
1. \( P<Q \)
2. \( S>P>T \)
3. \( R<T \)
If integers 1 through 5 are used to construct such a number, the value of P is:


