Question:

For a circuit shown below, when switch is closed, the current $I_2$(s) is (assume $i(0^+)=0)$

Updated On: Mar 21, 2024
  • $I_2(s)$ = $\frac 1{s+2.5} $
  • $I_2(s)$= $\frac 1{s(s+2.5) } $
  • $I_2(s)$ = $\frac {s}{s+2.5} $
  • $I_2(s)$= $\frac {s+2.5}{s(s+5)}$
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The Correct Option is B

Solution and Explanation

The Correct answer is option (B) : $I_2(s)$= $\frac 1{s(s+2.5) } $
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