Question:

For a Boolean variable \(x\), which of the following statements is/are FALSE?}

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Boolean algebra follows basic logic rules: \(x + 1 = 1\), \(x \cdot x = x\), and \(x + \overline{x} = 1\). Review these rules for accuracy.
Updated On: Jan 23, 2025
  • \(x \cdot 1 = x\)
  • \(x + 1 = x\)
  • \(x \cdot x = 0\)
  • \(x + \overline{x} = 1\)
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The Correct Option is B

Solution and Explanation

Option (A): This is true. The Boolean AND operation with 1 always yields the variable itself: \(x \cdot 1 = x\).
Option (B): This is false. The Boolean OR operation with 1 always yields 1, regardless of the value of \(x\): \(x + 1 = 1\).
Option (C): This is false. The Boolean AND operation with itself yields the variable itself: \(x \cdot x = x\), not 0.
Option (D): This is true. The Boolean OR operation with the complement of a variable always yields 1: \(x + \overline{x} = 1\). Final Answer: \[ \boxed{\text{(B), (C)}} \]
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